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Re: Est weight

At 08:51 PM 9/1/97 -0400, you wrote:
>I have a pumpkin that has an ovt total inches of 291. If you use the formula
>in Don Langevins book, "Dill's method", it shows an estimate of 552 pounds.
>By using the "Stelfplug method" of circumference only, it has an estimated
>weight of 500 lbs. Can anyone shed any light on this discrepancy. 
>
>The discrepancy is even larger when the pumpkins are smaller, say between
70-90 inches in circumference.  My suspicion is that Steflplug will be more
accurate through a wider range of sizes simply because it cubes the
circumference, which should help to take into account for the proportionate
increase in volume of the pumpkin.  Part of the formula for determining
volume of a sphere includes the cubing of the radius, as in Volume=(4xPixr
cubed)/3  (sorry I can't write this out properly). The tricky thing about
pumpkins is that they are not "solid" (or perfect) spheres, though the
volume is obviously one of the crucial things.  It is interesting, for
example, that an increase of  1 inch in circumference from 70"-71" yields an
increase in only 3 pounds, whereas the same increase from 168"-169" yields
18 pounds--according to the chart Don Langevin provides based on the
Stellpfug method.

I don't see anything in the Dill method that would account for the shifts in
volume, but I may just be missing something obvious.

Stephen
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