RE: lineage/genetics/characteristics

Scott

I'm also wondering why. And I think if we ask the right question we might 
get the answer here eventually.

Zachary

I'm impressed with your cell knowledge. But lets talk on my simple level. 
Ok when fertilization occurs, we have the combination of chromosomes in an 
orderly fashion. Lets simplify and say the male arranges its chromosomes 
(CZ for short) to be in the shape of a long ladder that has been cut down 
the center of the rungs ie.half a ladder cut lengthwise. So does the 
receiving female cell. Fertilization is the joining of the rungs to form a 
whole ladder. Right? In a perfect world the number of rungs and the length 
of each half ladder would be the same. Rungs X1-XN would be the knowledge 
rungs controlling lets say creation of roots, leaves, germination, wall 
thickness, etc. Upon joining all of these knowledge rungs should all line 
up exactly between the male and female CZs. Right.
You mentioned a possible reorganization of rungs "will have identical 
genetic
makeup for all the seed except for the recombination that has occurred 
among the chromosomes during meiosis". Is that what you are saying?

Further:" since recombination has occurred, segregation in the seeds
occurred.  Your alleles that make up the genes will be in different
combinations than the F1 hybrid plant which is totally uniform.  THe new
seed batch will be a mixture of plants that look like the A plant and some
that look like the B plant."

OK  I think what you are saying is that the rungs are all combining in the 
correct order, otherwise we might be getting seeds growing on the outside 
of the pumpkin ( which incidentally occurred on three of my pumpkins this 
year).

ZZZ)  Your last quote above to simplify says that for each ladder half 
there is only two possible ways of joining- 1 is with the A plant CZ join 
and 2 is the B plant CZ join. Is that correct?

Now it's my understanding that due to cross breeding that has occurred for 
the last 20 years or so (i.e.. 20 generations ) that ZZZ above it is not 
absolutely correct as I understand it that each rung has itself  4 ways of 
joining as follows: AA,AB,BB,BA is this correct? Now depending on how many 
CZ pairs we have (rungs) each pair has 4 ways of joining. Now assuming 10 
pairs each of which has 4 ways of joining the number of possible 
combinations for each resulting individual is 4 to the power 10 or 
approximately 1million possible ways of joining. If this is correct then 
each individual seed is not genetically similar but unique. What do you 
say?

Bob.
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