> In volume measurements the radius appears as the cube, the third
> power. Thus a diameter of 5 (radius 2.5) gives 15.625 while a diameter
> of 7 (radius 3.5) gives a 42.875. As you can see, the latter number is
> approaching three times that of the former. Thus the weight of the latter
> should be roughly three times that of the former.
Yes! The math is correct. The conclusion, however, assumes that each
tuber has equal mass throughout, I.e. no hard central core or the like.
I believe this is a correct assumption but have no intention of cutting
up one of mine to verify this!
Don Burns Plantation, FL USA
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