Re: HYB: pink probabilities


A Punnett square of a tttt X TTtt would look like this:

    TT     Tt      Tt    tT    tT      tt
_________________________
tt | TTtt   Tttt   Tttt   Tttt  Tttt    tttt
tt | TTtt   Tttt   Tttt   Tttt  Tttt    tttt
tt | TTtt   Tttt   Tttt   Tttt  Tttt    tttt
tt | TTtt   Tttt   Tttt   Tttt  Tttt    tttt
tt | TTtt   Tttt   Tttt   Tttt  Tttt    tttt
tt | TTtt   Tttt   Tttt   Tttt  Tttt    tttt

which gives 6/36ths, or one out of six  "tttt" recessives, as we've
indicated.

Think of it this way:  The gametes are chromosomes 1+2, 1+3, 1+4, 2+3, 2+4,
3+4 =six possible gametes (assuming random pairing).

Tttt X Tttt gives

    Tt   Tt  Tt  tt  tt tt  gametes for both parents.  The square produces
36 possible results.  Of these, 9 are tttt.  That gives a ratio of 1 out of
4 tttt possible.

TTtt X Tttt gives  3 out of 36, or 1/12th tttt results.

TTtt X TTtt gives 1 out of 36 tttt results, again assuming random pairing of
the four chromosomes.  That isn't always the case, however.

Does this help, Linda?

Neil Mogensen  z 7  Reg 4  western NC mountains

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